Question
If x4 occurs in the rth term in the expansion of (x4+1x3)16, then r =
Answer: Option C
:
C
Tr =16Cr−1 (x4)16−r(1x3)r−1 =16Cr−1x67−7r
→67−7r=4→r=9
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:
C
Tr =16Cr−1 (x4)16−r(1x3)r−1 =16Cr−1x67−7r
→67−7r=4→r=9
Was this answer helpful ?
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