Question
If the length of diagonals DF, AG and CE of the cube shown in the adjoining figure are equal to the three sides of a triangle, then the radius of the circle circumscribing that triangle will be :
Answer: Option A
:
A
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A
The side length of a cube = AD = a
The diagonal length of a cube = AG = a√3
DF = AG = CE = a√3
The triangle formed was an equilateral triangle.
The circumradius of an equilateral triangle = s√33
Therefore, the circumradius of that triangle = a√3√33
= Side of a cube
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