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In the given figure, EADF is a rectangle and ABC is a triangle whose vertices lie on the sides of EADF. AE = 22, BE =16, CF = 16, CF = 16 and BF = 2. Find the length of the line joining the
mid-points of the sides AB and BC.
(CAT 1997)
In The Given Figure, EADF Is A Rectangle And ABC Is A Triang...


Options:
A .   44
B .   5
C .   3.5
D .   none of these
Answer: Option B
:
B

Option (b)


EF = AD = 8


(EADF is a rectangle)


CD = (22 – 16) = 6


In The Given Figure, EADF Is A Rectangle And ABC Is A Triang...


So in the right angled triangle ADC, AD = 8 and CD = 6.


Therefore AC = 10


Therefore length of the line joining the mid – points of


AB and BC = 12 (10) = 5


(length of the line joining the mid – point of two sides of a triangle is half the 3\(^{rd}\)



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