Question
In the adjoining figure, points A, B, C and D lie on the circle, AD = 24 and BC = 12. What is the ratio of the area of triangle ΔCBE to that of the triangle ΔADE ? (CAT 1997)
Answer: Option A
:
A
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A
(b) In ΔCBE and ΔADE
CBA = CDA
(a chord of a circle subtends equal angle an all its circumference)
Similarily BCD = BAD and BEC = AED
(opp. angles)
Therefore ΔCBE ΔADE (AAA similarity rule)
Now BCDA=1224=12 Thus, ratios of areas = 1:4,
since Ratio of Areas of 2 similar triangles = Ratio of squares of the corresponding sides
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