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Question
If the ellipse x24+y21=1 meet the ellipse x21+y2a2=1 in four distinct points and a=b210b+25, then the value b does not satisfy
Options:
A .  (−∞,4)
B .  (4, 6)
C .  (6,−∞)
D .  [4, 6]
Answer: Option D
:
D
For the two ellipse to intersect at four different points
1<a21<(b5)2b/ϵ[4,6]

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