Question
If $$\sqrt {{\text{4096}}} $$Â = 64, then the value of $$\sqrt {{\text{40}}{\text{.96}}} $$ Â $$ + $$ $$\sqrt {{\text{0}}{\text{.4096}}} $$ Â $$ + $$ $$\sqrt {{\text{0}}{\text{.004096}}} $$ Â Â $$ + $$ $$\sqrt {{\text{0}}{\text{.00004096}}} $$ Â Â up to two place of decimals is = ?
Answer: Option C
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