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Question
If $$\sqrt {{\text{4096}}} $$  = 64, then the value of $$\sqrt {{\text{40}}{\text{.96}}} $$   $$ + $$ $$\sqrt {{\text{0}}{\text{.4096}}} $$   $$ + $$ $$\sqrt {{\text{0}}{\text{.004096}}} $$    $$ + $$ $$\sqrt {{\text{0}}{\text{.00004096}}} $$     up to two place of decimals is = ?
Options:
A .  7.09
B .  7.10
C .  7.11
D .  7.12
Answer: Option C

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