Question
If d2xdy2(dydx)3+d2ydx2=k, then k is equal to
Answer: Option A
:
A
dydx=(dxdy)−1⇒d2ydx2=−(dxdy)−2{ddx(dxdy)}⇒d2ydx2=−(dxdy)−2{ddy(dxdy)dydx}⇒d2ydx2=−(dydx)2{d2xdy2.dydx}⇒d2ydx2=−(dydx)3d2xdy2⇒d2ydx2+(dydx)3d2xdy2=0
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:
A
dydx=(dxdy)−1⇒d2ydx2=−(dxdy)−2{ddx(dxdy)}⇒d2ydx2=−(dxdy)−2{ddy(dxdy)dydx}⇒d2ydx2=−(dydx)2{d2xdy2.dydx}⇒d2ydx2=−(dydx)3d2xdy2⇒d2ydx2+(dydx)3d2xdy2=0
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