Question
If y=√x+√y+√x+√y+....∞, then dydx is equal to
Answer: Option B
:
B
∴y=√x+√y+y
⇒(y2−x)=√2y
or (y2−x)2=2y
Differentiating both sides w.r.t. x, then
2(y2−x)(2ydydx−1)=2dydx
∴dydx=(y2−x)2y3−2xy−1
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:
B
∴y=√x+√y+y
⇒(y2−x)=√2y
or (y2−x)2=2y
Differentiating both sides w.r.t. x, then
2(y2−x)(2ydydx−1)=2dydx
∴dydx=(y2−x)2y3−2xy−1
Was this answer helpful ?
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