If AM is a median of triangle ABC, then which of the following relation will always hold good?
Options:
A .  AB + BC + CA = 2AM
B .  AB + BC + CA > 2AM
C .  AB + BC + CA
D .  AB + BC + CA = AM
Answer: Option B : B Sum of lengths of any two sides of a triangle is always greater than the third side. Hence, AB + BM > AM AC + CM > AM Thus, AB + BC + CA > 2AM
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