Question
(a) If AB || DE, ∠AOD = 50° and ∠DPC = 160°, find the value of ∠DBE?
(b) A 15 m long ladder reached a window 12 m high from the ground when placed against a wall at a distance 'a'. Find the distance of the foot of the ladder from the wall.
[4 MARKS]
(b) A 15 m long ladder reached a window 12 m high from the ground when placed against a wall at a distance 'a'. Find the distance of the foot of the ladder from the wall.
[4 MARKS]
Answer:
:
(a)Steps: 1 Mark
Correct answer: 1 Mark
(b) Formula: 1 Mark
Result: 1 Mark
(a)
∠OAD=50°(given)∠DOC=180°−50°=130°(linearpair)∠DPC=160°(given)∠DPO=180°−160°(Linearpair)∠DPO=20°In△DOP∠ODP=180°−(130°+20°)(byanglesumproperty)∠ODP=30°In△DBE∠DBE=180°−(90°+30°)(Byanglesumproperty)∠DBE=60°
(b)
The wall and the ground are at right angle. Therefore the ladder,ground and the wall make the sides of a right-angled triangle.
∴a2+122=152
⇒a2=225−144=81
a=√81=9m
Was this answer helpful ?
:
(a)Steps: 1 Mark
Correct answer: 1 Mark
(b) Formula: 1 Mark
Result: 1 Mark
(a)
∠OAD=50°(given)∠DOC=180°−50°=130°(linearpair)∠DPC=160°(given)∠DPO=180°−160°(Linearpair)∠DPO=20°In△DOP∠ODP=180°−(130°+20°)(byanglesumproperty)∠ODP=30°In△DBE∠DBE=180°−(90°+30°)(Byanglesumproperty)∠DBE=60°
(b)
The wall and the ground are at right angle. Therefore the ladder,ground and the wall make the sides of a right-angled triangle.
∴a2+122=152
⇒a2=225−144=81
a=√81=9m
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution