Question
If 2x+2y=2x+y then the value of dydx at x=y=1 is
Answer: Option B
:
B
2x+2y=2x+y
∴2x.loge2+2y.loge2dydx=2x+y.loge2(1+dydx)
∴dydx=2x+y−2x2y−2x+y
dydx|x=y=1=−1
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:
B
2x+2y=2x+y
∴2x.loge2+2y.loge2dydx=2x+y.loge2(1+dydx)
∴dydx=2x+y−2x2y−2x+y
dydx|x=y=1=−1
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