Question
If y=(ax+bcx+d) , then 2dydx.d3ydx3 is equal to
Answer: Option C
:
C
∵y=(ax+bcx+d)orcxy+dy=ax+b
Differentiating both sides w.r.t.x, then
c{xdydx+y.1}+ddydx=aorxdydx+y+(dc)dydx=(ac)
Again differentiating both sides w.r.t.x, then
orxd2ydx2+dydx+dydx+(dc)d2ydx2=0orx+2dydx(d2ydx2)+dc=0
Again differentiating both sides w.r.t.x, then
1+2(d2ydx2.d2ydx2−dydx.d3ydx3)(d2ydx2)2+0=0∴2dydx.d3ydx3=3(d2ydx2)2
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:
C
∵y=(ax+bcx+d)orcxy+dy=ax+b
Differentiating both sides w.r.t.x, then
c{xdydx+y.1}+ddydx=aorxdydx+y+(dc)dydx=(ac)
Again differentiating both sides w.r.t.x, then
orxd2ydx2+dydx+dydx+(dc)d2ydx2=0orx+2dydx(d2ydx2)+dc=0
Again differentiating both sides w.r.t.x, then
1+2(d2ydx2.d2ydx2−dydx.d3ydx3)(d2ydx2)2+0=0∴2dydx.d3ydx3=3(d2ydx2)2
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