Question
If $2^{x - 1} + 2^{x + 1}$ = 320, then the value of x is
Answer: Option A
Answer:(b)$2^{x - 1} + 2^{x + 1}$ = 320$2^{x-1}(1+ 2^2) = 320$$2^{x-1} ×5 =320$$2^{x-1}= 320/5 =64 ⇒2^{x -1} = 2^{6}$$x - 1 = 6 ⇒ x = 7$
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Answer:(b)$2^{x - 1} + 2^{x + 1}$ = 320$2^{x-1}(1+ 2^2) = 320$$2^{x-1} ×5 =320$$2^{x-1}= 320/5 =64 ⇒2^{x -1} = 2^{6}$$x - 1 = 6 ⇒ x = 7$
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