Question
I. a2 - 13a + 42 = 0, II. b2 - 15b + 56 = 0 to solve both the equations to find the values of a and b?
Answer: Option D
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I. a2 - 13a + 42 = 0
=>(a - 6)(a - 7) = 0 => a = 6, 7
II. b2 - 15b + 56 = 0
=>(b - 7)(b - 8) = 0 => b = 7, 8
=>a ≤ b
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