Question
I. a2 + 8a + 16 = 0, II. b2 - 4b + 3 = 0 to solve both the equations to find the values of a and b?
Answer: Option A
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I. (a + 4)2 = 0 => a = -4
II.(b - 3)(b - 1) = 0
=> b = 1, 3 => a < b
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