Question
Given |→A+→B|=|→A−→B| Find the angle between →A and →B
Answer: Option C
:
C
A2+B2+2ABcosθ=A2+B2−2Acosθ⇒4ABcosθ=0⇒cosθ=0⇒θ=90∘
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:
C
A2+B2+2ABcosθ=A2+B2−2Acosθ⇒4ABcosθ=0⇒cosθ=0⇒θ=90∘
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