A mass m slips along a smooth hemispherical surface of radius R starting from

Question

A mass m slips along a smooth hemispherical surface of radius R starting from rest at the top as shown.
The velocity of the mass at the bottom of the surface is

Options:

A . √Rg

B . √2Rg

C . 2√πRg

D . 2√πRg

Answer: Option B
:
B
By applying law of conservation of energy
mgR =

\frac{1}{2} m v^{2}

\Rightarrow v = \sqrt{2 R g}

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