Question
Given that: Side of square ABCD = 4cm, E, F, G and H are midpoints of the sides AD, AB, BC and CD respectively. Also, the line passing through ON would bisect the line XF. Similar is the case for all other pairs: PO, RS and TM. Lastly, the lengths TM = NO = PQ = RS = 14 side of square (Note: The figure given below is a symmetric figure). X is the centre point of the square. The area of the shaded region is ___
Answer:
:
Using graphical division, we can divide the figure to look like the following:
Looking at the figure, we can easily make out that the shaded region is made out of 16 triangles,
Each being 1/64th the size of the larger square. (Since, area of each triangle =14 * 116 is area of square)
Therefore, area of shaded region = (14×116×16×16)cm2
Thus, required area of shaded region = 4cm2.
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:
Using graphical division, we can divide the figure to look like the following:
Looking at the figure, we can easily make out that the shaded region is made out of 16 triangles,
Each being 1/64th the size of the larger square. (Since, area of each triangle =14 * 116 is area of square)
Therefore, area of shaded region = (14×116×16×16)cm2
Thus, required area of shaded region = 4cm2.
Was this answer helpful ?
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