Gaseous Benzene reacts with hydrogen gas in presence of a Nickel catalyst to for

Question

Gaseous Benzene reacts with hydrogen gas in presence of a Nickel catalyst to form gaseous cyclohexane according to the Reaction

C_{6} H_{6} + 3 H_{2} ⟶ C_{6} H_{12}

A mixture of

C_{6} H_{6}

and excess

H_{2}

has a pressure of 60mm of Hg in an unknown volume. After the gas had been passed over a Ni catalyst and all the benzene converted to cyclohexane, the pressure of the gas was 30mm of Hg in the same volume at the same temperature. The fraction of

C_{6} H_{6}

(by volume) present in the original volume is

Options:

A . 13

B . 14

C . 15

D . 16

Answer: Option D
:
D
Let initial pressure of

C_{6} H_{6} = P_{1} m m .

And that of

H_{2} = P_{2} m m .

∴ P_{1} + P_{2} = 60 m m . ⟶ (1)

After the Reaction, pressure of

C_{6} H_{6} = 0

(As all has reacted)
Pressure of

H_{2} = P_{2} - 3 P_{1}

Pressure of

C_{6} H_{16} = P_{1}

Total Pressure =

P_{2} - 3 P_{1} + P_{1} = 30 m m

Or,

P_{2} - 2 P_{1} = 30 m m ⟶ (2)

Solving (1) and (2) we get

P_{1} = 10 m m, P_{2} = 50 m m

Fraction of

C_{6} H_{6}

by volume = fraction of moles = fraction of pressure =

\frac{10}{60} = \frac{1}{6}

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