'x' moles of N 2 gas at S.T.P conditions occupy a volume of 10 litres, then the volume of '2x' moles of C H 4 at 273 0 C and 1.5 atm is Options: A . &nbsp20 lit B . &nbsp26.6 lit C . &nbsp5 lit D . &nbsp16.6 lit

Answer: Option B : B P 1 V 1 n 1 T 1 = P 2 V 2 n 2 T 2 1 × 10 n × 273 = 1.5 × V 2 2 x × 546 V 2 = 26.6 l i t

'x' moles of N2 gas at S.T.P conditions occupy a volume of 10 litres,

Question

'x' moles of

N_{2}

gas at S.T.P conditions occupy a volume of 10 litres, then the volume of '2x' moles of

C H_{4}

273^{0} C

and 1.5 atm is

Options:

A . 20 lit

B . 26.6 lit

C . 5 lit

D . 16.6 lit

Answer: Option B
:
B

\frac{P_{1} V_{1}}{n_{1} T_{1}} = \frac{P_{2} V_{2}}{n_{2} T_{2}}

\frac{1 \times 10}{n \times 273} = \frac{1.5 \times V_{2}}{2 x \times 546}

V_{2} = 26.6 l i t

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