12th Grade > Chemistry
STATES OF MATTER MCQs
Total Questions : 30
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Answer: Option D. -> 8P
:
D
P1V1 =P2V2
P. l3 = p2 (12)3
P2 = 8P
:
D
P1V1 =P2V2
P. l3 = p2 (12)3
P2 = 8P
Answer: Option C. -> Critical temperature
:
C
This is the definition of critical temperature.
:
C
This is the definition of critical temperature.
Answer: Option A. -> 25.215 atm
:
A
No. of moles of O2=432=0.125
No.of moles of H2=22=1
Total no. of moles = 1+0.125 = 1.125
P=nRTV=1.125×0.082×2731=25.215atm
:
A
No. of moles of O2=432=0.125
No.of moles of H2=22=1
Total no. of moles = 1+0.125 = 1.125
P=nRTV=1.125×0.082×2731=25.215atm
Answer: Option B. -> Same as that of a hydrogen molecule
:
B
EHeEH2=√THeTH2 so energies will be same for
He & H2 at same temperature.
:
B
EHeEH2=√THeTH2 so energies will be same for
He & H2 at same temperature.
Answer: Option B. -> SO2
:
B
Speed is inversely proportional to molecular weight. Molecular weight of SO2 is highest among the four. Hence its speed is least.
:
B
Speed is inversely proportional to molecular weight. Molecular weight of SO2 is highest among the four. Hence its speed is least.
Answer: Option B. -> 0∘C, 2atm
:
B
For an ideal gas, density(d) will be the maximum when Pressure is high and the temperature is low.
d=PMRT(or)d∝PT
Therefore option B is correct as it satisfies these conditions.
:
B
For an ideal gas, density(d) will be the maximum when Pressure is high and the temperature is low.
d=PMRT(or)d∝PT
Therefore option B is correct as it satisfies these conditions.
Answer: Option C. -> 1.52
:
C
rxrO2=√MO2Mx=⟮45⟯2=32Mx⇒Mx=50
dx=0.80kgm−3
Vm=1000800×50=62.5L
Z=PVmRT=1×62.50.0821×500=1.52
:
C
rxrO2=√MO2Mx=⟮45⟯2=32Mx⇒Mx=50
dx=0.80kgm−3
Vm=1000800×50=62.5L
Z=PVmRT=1×62.50.0821×500=1.52
Answer: Option B. -> 2
:
B
rHerCH4=√MCH4MHe⇒√(164)⇒2
:
B
rHerCH4=√MCH4MHe⇒√(164)⇒2
Answer: Option D. -> The mean translational kinetic energy of the molecules is proportional to the absolute temperature
:
D
All molecules of an ideal gas show random motion. They collide with each other and walls of container during which they lose or gain energy so they may not have same kinetic energy always.
:
D
All molecules of an ideal gas show random motion. They collide with each other and walls of container during which they lose or gain energy so they may not have same kinetic energy always.
Answer: Option C. -> 0.96 atm
:
C
Pressure ofO2(dry) = 751 - 21 = 730 mm Hg = 730760= 0.96 atm
:
C
Pressure ofO2(dry) = 751 - 21 = 730 mm Hg = 730760= 0.96 atm