For the toppling of the hexagon as shown in the figure, the coefficient of frict

Question

For the toppling of the hexagon as shown in the figure, the coefficient of friction must be

Options:

A . > 0.21

B . < 0.21

C . = 0.21

D . < 0.21

Answer: Option A
:
A
To prevent slipping

F = μ N = μ m g

the body will topple about point O, if

F . h \geq m g \frac{a}{2}

here h = 2a

cos

30^{\circ}

a \sqrt{3}

μ m g a \sqrt{3} \geq m g \frac{a}{2}

μ \geq \frac{1}{2 \sqrt{3}}

μ \geq 0.21

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