An automobile engine develops 100 kW when rotating at a speed of 1800 rev/min. W

Question

An automobile engine develops 100 kW when rotating at a speed of 1800 rev/min. What torque does it deliver

Options:

A . 350 N-m

B . 440 N-m

C . 531 N-m

D . 628 N-m

Answer: Option C
:
C

P = τ ω \Rightarrow τ = \frac{100 \times 10^{3}}{2 π \frac{1800}{60}} = 531 N - m

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