Question
A uniform wheel of moment of inertia 'I' is pivoted on a horizontal axis through its centre so that its plane is vertical as shown in the figure. A small mass 'm' is stuck on the rim of the wheel as shown. The angular acceleration of the wheel when mass is at point A is αA and when mass is at point B is αB. Then,
Answer: Option C
:
C
The torque due to the weight of m at A is τAand that when it is at B is τB
⇒τBτA=IαBIαA=bcosθb=cosθ.
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:
C
The torque due to the weight of m at A is τAand that when it is at B is τB
⇒τBτA=IαBIαA=bcosθb=cosθ.
Was this answer helpful ?
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