Question
For a triangle ABC, D and E are two points on AB and AC such that AD = $$\frac{1}{4}$$ AB, AE = $$\frac{1}{4}$$ AC. If BC = 12 cm, then DE is :
Answer: Option C
According to question,
By using B.P.T
$$\eqalign{
& \frac{{AD}}{{AB}} = \frac{{AE}}{{AC}} = \frac{{DE}}{{BC}} \cr
& \frac{{AD}}{{AB}} = \frac{{DE}}{{BC}} \cr
& \Rightarrow \,\frac{1}{4} = \frac{{DE}}{{12}} \cr
& \Rightarrow DE = 3\,{\text{cm}} \cr} $$
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According to question,
By using B.P.T
$$\eqalign{
& \frac{{AD}}{{AB}} = \frac{{AE}}{{AC}} = \frac{{DE}}{{BC}} \cr
& \frac{{AD}}{{AB}} = \frac{{DE}}{{BC}} \cr
& \Rightarrow \,\frac{1}{4} = \frac{{DE}}{{12}} \cr
& \Rightarrow DE = 3\,{\text{cm}} \cr} $$
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