Question
In a ΔABC, If 2∠A = 3∠B = 6∠C, then the value of ∠B is:
Answer: Option A
According to question,
Given :
$$\eqalign{
& 2\angle A = 3\angle B \cr
& \frac{{\angle A}}{{\angle B}} = \frac{3}{2}\,\,\,\,\,\,\,\,\,\,\,\,\,3\angle B = 6\angle C \cr
& \frac{{\angle B}}{{\angle C}} = \frac{6}{3} = \frac{2}{1} \cr} $$
To make angle ∠B same
∴ ∠A : ∠B : ∠C
3 : 2 : 1
As we know that
∠A + ∠B + ∠C = 180°
3x + 2x + x = 180°
x = 30°
∠B = 2x
∠B = 60°
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According to question,
Given :
$$\eqalign{
& 2\angle A = 3\angle B \cr
& \frac{{\angle A}}{{\angle B}} = \frac{3}{2}\,\,\,\,\,\,\,\,\,\,\,\,\,3\angle B = 6\angle C \cr
& \frac{{\angle B}}{{\angle C}} = \frac{6}{3} = \frac{2}{1} \cr} $$
To make angle ∠B same
∴ ∠A : ∠B : ∠C
3 : 2 : 1
As we know that
∠A + ∠B + ∠C = 180°
3x + 2x + x = 180°
x = 30°
∠B = 2x
∠B = 60°
Was this answer helpful ?
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