Question
In ΔABC, AD ⊥ BC and AD2 = BD × DC. The measure of ∠BAC is :
Answer: Option B
AD2 = BD.DC
ΔADC ∼ ΔCAB (Property of a right angle Δ)
∠BAC = ∠ADC = 90°
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AD2 = BD.DC
ΔADC ∼ ΔCAB (Property of a right angle Δ)
∠BAC = ∠ADC = 90°
Was this answer helpful ?
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