Question
In a ΔABC, ∠A + ∠B = 118°, ∠A + ∠C = 96°. Find the value of ∠A.
Answer: Option D
According to question,
  ∠A + ∠B = 118°
  ∠A + ∠C = 96°
  ∠A = ?
As we know that
  ∠A + ∠B + ∠C = 180°
  ∠C = 180° - (∠A + ∠B)
  ∠C = 180° - 118°
∴ ∠C = 62°
  ∠A = 96° - 62°
  ∠A = 34°
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According to question,
  ∠A + ∠B = 118°
  ∠A + ∠C = 96°
  ∠A = ?
As we know that
  ∠A + ∠B + ∠C = 180°
  ∠C = 180° - (∠A + ∠B)
  ∠C = 180° - 118°
∴ ∠C = 62°
  ∠A = 96° - 62°
  ∠A = 34°
Was this answer helpful ?
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