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Answer: Option A
:
Each part: 1.5 Marks
(a) Let the triangle be ABC with ∠A being x and ∠B being the right angle.
In a triangle, Sum of opposite interior angles = exterior angle
Here,
x + 90o = 150o
Or, x = 150o - 90o = 60o
(b) ∠BAC=70∘ (Vertically opposite angles)
∠ABC=40∘ (Alternate angles)
x=180−(40+70) (Sum of angles in a triangle is 180∘
x=180−110=70∘
Was this answer helpful ?
:
Each part: 1.5 Marks
(a) Let the triangle be ABC with ∠A being x and ∠B being the right angle.
In a triangle, Sum of opposite interior angles = exterior angle
Here,
x + 90o = 150o
Or, x = 150o - 90o = 60o
(b) ∠BAC=70∘ (Vertically opposite angles)
∠ABC=40∘ (Alternate angles)
x=180−(40+70) (Sum of angles in a triangle is 180∘
x=180−110=70∘
Was this answer helpful ?
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