(a) For any triangle ABC, draw: [4 MARKS] (i) All possible medians. (ii) All possible altitudes. (b) Find the unknown angles x and y.
Options:
Answer: Option A : (a) Each sub-part: 1 Mark (b) Each angle: 1 Mark (a) (i) (ii) (b) ∠BAC=92∘ ∠ACB=x∘ (Equal sides have equal angles opposite to them.) ∠ACB+∠ABC+92∘=180∘ 2x+92∘=180∘ x+46∘=90∘ x=90∘−46∘ x=44∘ ∠ACB+y=180∘⇒x+y=180∘ ⇒44∘+y=180∘ ⇒y=180∘−44∘ ⇒y=136∘
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