Question
Divide (a2+7a+10) by (a+5).
Answer: Option D
:
D
Was this answer helpful ?
:
D
Given: a2+7a+10(a+5) ...(i)
Comparing a2+7a+10 with the identity x2+(a+b)x+ab,
we note that,(a+b)=7 and ab=10
So, 5+2=7 and (5)(2)=10
Hence,
a2+7a+10
=a2+5a+2a+10
=a(a+5)+2(a+5)
=(a+2)(a+5)
From (i), we get
a2+7a+10(a+5)=(a+2)(a+5)(a+5)
=(a+2)
Was this answer helpful ?
More Questions on This Topic :
Question 1.
Divide m2+7m−60 by (m−5).
....
Question 2.
Factorise: 25+70x+49x2
....
Question 4.
On dividing (24xy2)(z2) by 6yz2, we get
....
Question 8.
Find the common factor between
2t,3t2and 4.
....
Question 9.
Factorise:4y2−12y+9
....
Submit Solution