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Question
Construct ΔPQR, given ¯¯¯¯¯¯¯¯PQ=3.5 cm,¯¯¯¯¯¯¯¯PR=3 cm, and ∠RPQ=120∘  [4 MARKS]
Answer:
:
Construction: 2 Marks
Steps: 2 Marks
Draw ¯¯¯¯¯¯¯¯PQ=3.5cm
Construct ∠XPQ=120∘ with your compass.
With P as centre, draw an arc with radius equal to 3 cm that intersects ¯¯¯¯¯¯¯¯¯XP at point R.
Join ¯¯¯¯¯¯¯¯¯RQ
PQR is the required triangle.
Construct ΔPQR, Given ¯¯¯¯¯¯¯¯PQ=3.5 cm,¯¯¯¯¯...
Thus, we see that if two sides of a triangle are given and the measure of the angle between these two sides is also given, then we can construct a triangle. This is known as SAS criterion for construction of triangles.

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