Question
Incenter of ΔABC is I. ∠ABC = 90° and ∠ACB = 70°. ∠BIC is:
Answer: Option B
∵ Sum of all angles of a triangle = 180°
So, ∠BAC = 180 - (90 + 70)
∠BAC = 20°
So, ∠BIC = 90 + $$\frac{1}{2}$$ ∠A
∠BIC = 90° + $$\frac{1}{2}$$ × 20°
∠BIC = 100°
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∵ Sum of all angles of a triangle = 180°
So, ∠BAC = 180 - (90 + 70)
∠BAC = 20°
So, ∠BIC = 90 + $$\frac{1}{2}$$ ∠A
∠BIC = 90° + $$\frac{1}{2}$$ × 20°
∠BIC = 100°
Was this answer helpful ?
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