A tower is 100√3 m high. Find the angle of elevation of its top from a point

Question

A tower is 100

\sqrt{3}

m high. Find the angle of elevation of its top from a point 100 m away from its foot.

Options:

A . 30∘

B . 60∘

C . 45∘

D . 15∘

Answer: Option B
:
B

Let the angle of elevation be

θ

\Rightarrow

t a n θ

\frac{P e r p e n d i c u l a r}{B a s e}

\Rightarrow

t a n θ

\frac{100 \sqrt{3}}{100}

\sqrt{3}

Therefore,

θ

60^{\circ}

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