A person observes the angle of elevation of the top of a 60m tower from a point on the level ground to be 60 ∘ . Find the distance between the person and the foot of the tower. Options: A . &nbsp30 m B . &nbsp20√3 m C . &nbsp20 m D . &nbsp60 m

Answer: Option B : B In Δ A B C ,tan(60 ∘ ) = B C A B ⇒ √ 3 = 60 x ⇒ x = 20 √ 3 ⇒ Distance between the person and the tower = x = 20 √ 3 m.

A person observes the angle of elevation of the top of a 60m tower from a point

Question

A person observes the angle of elevation of the top of a 60m tower from a point on the level ground to be 60

^{\circ}

. Find the distance between the person and the foot of the tower.

Options:

A . 30 m

B . 20√3 m

C . 20 m

D . 60 m

Answer: Option B
:
B

Δ A B C

,tan(60

^{\circ}

) =

\frac{B C}{A B}

\Rightarrow

\sqrt{3} = \frac{60}{x}

\Rightarrow

x = 20

\sqrt{3}

\Rightarrow

Distance between the person and the tower = x = 20

\sqrt{3}

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