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Question
A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?
Options:
A .  58 l
B .  62 l
C .  50 l
D .  65 l
Answer: Option C

Let the tin contain 5x litres of liquids 5 x   -   45   x   4 5 5 x   -   45   x   1 5   +   45   =   2 5 => 5(4x - 36) = 2(x + 36) => 20x - 180 = 2x + 72 => x = 14 litres Hence, the initial quantity of mixture = 70l Quantity of liquid B =  70   -   45   x   1 5   +   45   = 50 litres.



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