Question
A particle is moving along the path given by y = c6 t6(where c is positive constant). The relation between the acceleration (a) and the velocity (v) of the particle at t=5 sec. Is
Answer: Option D
:
D
Differentiate y we get v=c(t5)
Differentiate v we get a=5c(t4)
In expressions for v and a, substitute t = 5 s and take ratio of the two quantities.
We get, v=a
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:
D
Differentiate y we get v=c(t5)
Differentiate v we get a=5c(t4)
In expressions for v and a, substitute t = 5 s and take ratio of the two quantities.
We get, v=a
Was this answer helpful ?
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