Question
A body A is projected upwards with a velocity of 98 m/s. The second body B is projected upwards with the same initial velocity but after 4 sec. Both the bodies will meet after
Answer: Option D
:
D
Let tbe the time of flight of the first body when they meet.
Then the time of flight of the second body will be(t - 4)sec.
Since the displacementof both the bodies from the ground will be the same,
h1=h2
∴98t−12gt2=98(t−4)−12g(t−4)2
On solving, we get t = 12 seconds.
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:
D
Let tbe the time of flight of the first body when they meet.
Then the time of flight of the second body will be(t - 4)sec.
Since the displacementof both the bodies from the ground will be the same,
h1=h2
∴98t−12gt2=98(t−4)−12g(t−4)2
On solving, we get t = 12 seconds.
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