Question
A block of mass 5.0 kg slides down from the top of an inclined plane of length 3 m. The first 1 m of the plane is smooth and the next 2 m is rough. The block is released from rest and again comes to rest at the bottom of the plane. If the plane is inclined at 30∘ with the horizontal, find the coefficient of friction on the rough portion.
Answer: Option B
:
B
Force Method:
Form P to Q: v2=O2+2a1S1
Where a1=gsin30∘,s1=1m
And form Q to R: O2=v2+2a2s2
Where a2=gsin30∘−μgcos30∘,s2=2m
Solve to get μ=√32
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:
B
Force Method:
Form P to Q: v2=O2+2a1S1
Where a1=gsin30∘,s1=1m
And form Q to R: O2=v2+2a2s2
Where a2=gsin30∘−μgcos30∘,s2=2m
Solve to get μ=√32
Was this answer helpful ?
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