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A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of the heaviest fragment will be
 
Options:
A .  11.5 m/s
B .  14.0 m/s
C .  7.0 m/s
D .  9.89 m/s
Answer: Option D
:
D
A Body Of Mass 5 Kg Explodes At Rest Into Three Fragments Wi...
Px=m×vx=1×21=21kgm/s
Py=m×vy=1×21=21kgm/s
Resultant = P2x+P2y=212kgm/s
The momentum of heavier fragment should be numerically equal to resultant of Px and Py.
3×v=P2x+P2y=212v=72=9.89m/s

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