Question
A neutron of mass 1.67×10−27kg is moving with a velocity 1.2×107ms−1 collides head-on with a deuteron of mass 3.34×10−27kg initially at rest. If the collision is perfectly inelastic, the speed of the composite particle will be
Answer: Option B
:
B
Mass of neutron (m) = 1.67×10−27 kg. Speed of neutron (v) = 1.2×107ms−1.Notice that the mass ofdeuteron (M) = 3.34×10−27kg=2m. If V is the speed of the composite particle, the law of conservaton of momentum gives mv = (m+M)V
or V=mvm+M=mvm+2m
or V=v3=1.2×1073=4×106ms−1, which is choice (b).
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:
B
Mass of neutron (m) = 1.67×10−27 kg. Speed of neutron (v) = 1.2×107ms−1.Notice that the mass ofdeuteron (M) = 3.34×10−27kg=2m. If V is the speed of the composite particle, the law of conservaton of momentum gives mv = (m+M)V
or V=mvm+M=mvm+2m
or V=v3=1.2×1073=4×106ms−1, which is choice (b).
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