Question
A body of mass m1 moving at a constant speed undergoes an elastic collision with a body of mass m2 initially at rest. The ratio of the kinetic energy of mass m1 after the collision to that before the collision is
Answer: Option A
:
A
Let u1 be the speed of mass m1 before the collision.
Here u2=0. Therefore, the speeds of masses m1 and m2 after the collision respectively are
v1=(m1−m2m1+m2)u1
and v2=(2m1m1+m2)u1
∴KE of m1 after collision = 12m1v21=12m1(m1−m2m1+m2)2u21. KE of m1 before collision = 12m1u21.
The ratio of the two is (m1−m2m1+m2)2. Hence the correct choice is (a)
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A
Let u1 be the speed of mass m1 before the collision.
Here u2=0. Therefore, the speeds of masses m1 and m2 after the collision respectively are
v1=(m1−m2m1+m2)u1
and v2=(2m1m1+m2)u1
∴KE of m1 after collision = 12m1v21=12m1(m1−m2m1+m2)2u21. KE of m1 before collision = 12m1u21.
The ratio of the two is (m1−m2m1+m2)2. Hence the correct choice is (a)
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