Question
A body of mass 2 kg moving with a velocity (^i+2^j−3^k) ms−1 collides with another body of mass 3 kg moving with a velocity (2^i+^j+^k) in ms−1. If they stick together, the velocity in ms−1 of the composite body is
Answer: Option A
:
A
p1=2kg(^i+2^j−3^k)ms−1=(2^i+4^j−6^k)kgms−1p2=3kg(2^i+^j+^k)ms−1=(6^i+3^j+3^k)kgms−1
Resultant momentum is
p=p1+p2
=(2^i+4^j−6^k)+(6^i+3^j+3^k)
=(8^i+7^j−3^k)kgms−1
Total mass (m) = 2 + 3 = 5 kg. Therefore, the velocity of composite body is
v=pm=15(8^i+7^j−3^k)ms−1
Hence the correct choice is (a).
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:
A
p1=2kg(^i+2^j−3^k)ms−1=(2^i+4^j−6^k)kgms−1p2=3kg(2^i+^j+^k)ms−1=(6^i+3^j+3^k)kgms−1
Resultant momentum is
p=p1+p2
=(2^i+4^j−6^k)+(6^i+3^j+3^k)
=(8^i+7^j−3^k)kgms−1
Total mass (m) = 2 + 3 = 5 kg. Therefore, the velocity of composite body is
v=pm=15(8^i+7^j−3^k)ms−1
Hence the correct choice is (a).
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