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  1. A, B and C completed a piece of work. A worked for 6 days. B for 9 days and C for 4 days. Their daily wages were in ratio of 3 : 4 : 5. Find the daily wage of C, if their total earning was Rs 1480.

Options:
A .  Rs 80
B .  Rs 75
C .  Rs 70
D .  Rs 65
Answer: Option A
Let the daily wage of A be 3x, daily wage of B be 4x and daily wage of C be 5x.
Given that, A worked for 6 days, B worked for 9 days and C worked for 4 days.
The total earnings of A = 3x * 6 = 18xThe total earnings of B = 4x * 9 = 36xThe total earnings of C = 5x * 4 = 20x
The total earnings of A, B and C = 18x + 36x + 20x = 74x
Given that, the total earnings of A, B and C is Rs. 1480. So, 74x = 1480x = 1480/74 = 20
Therefore, the daily wage of C = 5x = 5 * 20 = Rs. 100.
Hence, the answer is Option A: Rs 80.
Explanation:
  • The given problem is a ratios and proportions problem, where we have to find the daily wage of one person given the ratios of their daily wages and the total earnings.
  • We start by assuming a value of x as the daily wage of one person, and find the values of the other two based on their ratios.
  • Then we calculate the total earnings of each person based on the number of days they worked and their daily wages.
  • Finally, we find the total earnings of all three people and equate it to the given value of Rs. 1480.

  • Solving for x, we find that x = 20. Hence, the daily wage of C = 5x = Rs. 80.

If you think the solution is wrong then please provide your own solution below in the comments section .


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1 Comments

Daily wages are in the ratio 3:4:5
Let daily wage of A=3x
B=4x
C=5x
A works for 6 days so his wage = 3x×6=18x
B works for 9 days so his wage =4x×9= 36x
C works for 4 days so his wage =5x×4=20x
18x+36x+20x=1480
=> 74x=1480
=> x =1480/74
=> x =20
Hence x=20 & c works for 4 days so his wage is 4×20=80

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