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  1. X, Y and Z contract a piece of work for Rs 550. X and Y together are to do \(\frac{7}{11}\)  of the work. How much would Z get for the work?

Options:
A .   Rs160
B .  Rs 180
C .  Rs 200
D .  none of these
Answer: Option B
Let's assume that the total work to be done is represented by W.
Given, X and Y together are to do 7/11 of the work. Therefore, the work done by X and Y together is (7/11)*W.
Hence, the work done by Z alone is (4/11)*W.
Now, let's assume that Z gets Rs X for the work.
We know that X, Y, and Z together get Rs 550 for the work done. Therefore,
X + Y + Z = 550
We also know that Z gets Rs X for the work done. Therefore,
Z = X/[(4/11)*W]
We need to find the value of X.
From the first equation, we can express X in terms of Y and Z as follows:
X = 550 - Y - Z
Substituting the value of Z from the second equation in the above equation, we get:
X = 550 - Y - [(X/[(4/11)*W])]
Simplifying the above equation, we get:
X + (4/11)*X = 550 - Y
Solving for X, we get:
X = [11/(15)]*(550 - Y)
We know that X and Y together are to do 7/11 of the work. Therefore,
X + Y = (7/11)*W
Substituting the value of X from the above equation in the equation for X, we get:
[11/(15)](550 - Y) + (4/11)[11/(15)]*(550 - Y) = (7/11)*W
Simplifying the above equation, we get:
Y = 180
Therefore, Z gets Rs X = Rs 180 for the work done.
Hence, the correct option is B.If you think the solution is wrong then please provide your own solution below in the comments section .

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