A and B together can do a piece of work in 30 days. A having worked for 16 days,

Question

A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?

Options:

A . 30 days

B . 40 days

C . 60 days

D . 70 days

Answer: Option C

Let A's 1 day's work = x and B's 1 day's work = y.

Then , x+y = \(\frac{1}{30}\) and 16x + 44y = 1.

lving these two equations, we get: x = \(\frac{1}{60}\) and y = \(\frac{1}{60}\)

Therefore , B's 1 day's work = \(\frac{1}{60}\)

Hence, B alone shall finish the whole work in 60 days.

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Subhendu948 2016-06-09 13:30:19

Great material

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