Question
6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in_______days.
Answer: Option A
LET WORK DONE BY 1 MAN IN 1 DAY = M AND WORK DONE BY 1 WOMAN IN 1 DAY = B
WORK DONE BY 6 MEN AND 8 WOMEN IN 1 DAY = 1/10
=> 6M + 8B = 1/10
=> 60M + 80B = 1 — (1)
WORK DONE BY 26 MEN AND 48 WOMEN IN 1 DAY = 1/2
=> 26M + 48B = ½
=> 52M + 96B = 1— (2)
SOLVING EQUATION 1 AND EQUATION 2. WE GET M = 1/100 AND B = 1/200
WORK DONE BY 15 MEN AND 20 WOMEN IN 1 DAY
= 15/100 + 20/200 =1/4
=> TIME TAKEN BY 15 MEN AND 20 WOMEN IN DOING THE WORK = 4 DAYS
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LET WORK DONE BY 1 MAN IN 1 DAY = M AND WORK DONE BY 1 WOMAN IN 1 DAY = B
WORK DONE BY 6 MEN AND 8 WOMEN IN 1 DAY = 1/10
=> 6M + 8B = 1/10
=> 60M + 80B = 1 — (1)
WORK DONE BY 26 MEN AND 48 WOMEN IN 1 DAY = 1/2
=> 26M + 48B = ½
=> 52M + 96B = 1— (2)
SOLVING EQUATION 1 AND EQUATION 2. WE GET M = 1/100 AND B = 1/200
WORK DONE BY 15 MEN AND 20 WOMEN IN 1 DAY
= 15/100 + 20/200 =1/4
=> TIME TAKEN BY 15 MEN AND 20 WOMEN IN DOING THE WORK = 4 DAYS
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