Question
△ABC is such thatAB=3 cm,BC=2 cm and CA=2.5 cm. △DEF is similar to △ABC. If EF=4 cm, then the perimeter of △DEF is ____.
Answer: Option B
:
B
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B
ABDE =ACDF = BCEF = 24 = 12
DE=2×AB=6 cm,DF=2×AC=5 cm.
∴ Perimeter of ΔDEF=(DE+EF+DF)
=6+4+5=15 cm.
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