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10th Grade > Mathematics

TRIANGLES MCQs

Total Questions : 58 | Page 1 of 6 pages
Question 1. In below shown figure, PSSQ= PTTR andPST= PRQ. Then ΔPQR is a/an __ triangle.
In Below Shown Figure, PSSQ= PTTR And∠PST= ∠PRQ. Then Δ...
 Discuss Question

:
It is given that
PSSQ = PTTR
So, ST||QR [By converse of Basic Proportionality Theorem]
, PST=PQR (Corresponding Angles)
Also, it is given that
PST = PRQ
So,PRQ =PQR
Therefore, PQ = PR (Sides opposite the equal angles)
i.e., ΔPQR is an isosceles triangle.
Question 2. In triangle ABC, D is a point on AB and E is a point on AC such that DE || BC. If ADAB = AEx, Then x is
___.
 Discuss Question

:
In ABC,
DE BC (Given)
Therefore, ADAB = AEAC [By Basic Proportionality Theorem]
Comparing the above withADAB = AEx
x = AC
Question 3. In a right ABC, a perpendicular BD is drawn on  to the largest side from the opposite vertex. Which of the following does not give the ratio of the areas of ABD and ACB?
In A Right △ABC, A Perpendicular BD Is Drawn On  to The L...
  1.    (ABAC)2 
  2.    (ADAB)2 
  3.    (BDCB)2 
  4.    (ABAD)2 
 Discuss Question
Answer: Option D. -> (ABAD)2 
:
D
Consider ΔABD andΔACB:In A Right △ABC, A Perpendicular BD Is Drawn On  to The L...
∠BAD = ∠BAC [common angle]
∠BDA = ∠ABC [90]
By AA similarity criterion,
ABD~ACB
Hence,
ar(ΔABD)ar(ΔACB)=(ABAC)2=(ADAB)2=(BDCB)2
Question 4. The ratio of the corresponding sides of two similar triangles is 1 : 3. The ratio of their corresponding heights is _________.
  1.    1:3
  2.    3:1
  3.    1:9
  4.    9:1
 Discuss Question
Answer: Option A. -> 1:3
:
A
If two triangles are similar, then the ratio of the corresponding sides are equal.
Hence,
the ratio of heights = the ratio of sides = 1 : 3.
Question 5. In both the figures given below, all of the respective sides are equal and all interior angles are 90. Are the figures shown below similar?
In Both The Figures Given Below, All Of The respective Side...
  1.    True
  2.    False
  3.    4.2 cm
  4.    0.525 cm
 Discuss Question
Answer: Option A. -> True
:
A
Both the figures are similar as all the corresponding angles are equal and all the corresponding sides are in the same ratio as all the sides of both the figures are equal.
Ratio of corresponding sides = 4.22.1=2
Question 6. A farmer had three land plots as shown. He has to divide the plots equally among 2 of his sons. He gives Area a and Area b to one of his son and third Area c to his second son. Did he give equal land plots to both of his son?
Enter True if he has given equal area else enter false.
A Farmer Had Three Land Plots As Shown. He Has To Divide The...
  1.    True
  2.    False
  3.    81 : 16
  4.    16 : 81
 Discuss Question
Answer: Option A. -> True
:
A
Pythagoras theorem states that a2+b2=c2
So he did correct i.e. he divided the land equally among his two sons.
Question 7. In ΔABC, AB=BC=6cm. If a circle is drawn with center at B and radius 2 cm which intersects AB and BC at E and D, then ΔABCΔEBD.
In ΔABC, AB=BC=6cm. If A Circle Is Drawn With Center At B ...
  1.    True
  2.    False
  3.    MB = 5 cm
  4.    AC = 5 cm
 Discuss Question
Answer: Option A. -> True
:
A
In ΔABC, AB=BC=6cm. If A Circle Is Drawn With Center At B ...
In ΔABCandΔEBD,
BEBA=BDBC=26=13andDBE=ABC.
By SAS similarity,
ΔABC and ΔEBD are similar.
Question 8. In  ABC, A and C are given, the number of triangles that can be constructed with this data is -
  1.    One
  2.    Two
  3.    Three
  4.    Infinite
 Discuss Question
Answer: Option D. -> Infinite
:
D
S=180o(A+C)
The angles of the traingle are known. With the given measurement of the angles, we can draw infinite number of traingles (Similar triangles).
Question 9. ABC is such thatAB=3 cm,BC=2 cm and CA=2.5 cm. DEF is similar to ABC. If EF=4 cm, then the perimeter of DEF is ____.
  1.    7.5 cm  
  2.    15 cm  
  3.    22.5 cm 
  4.    30 cm
 Discuss Question
Answer: Option B. -> 15 cm  
:
B
ABDE =ACDF =BCEF =24 =12
DE=2×AB=6cm,DF=2×AC=5cm.
Perimeter ofΔDEF=(DE+EF+DF)
=6+4+5=15cm.
Question 10.  A ladder is resting on a wall of height       107m such that the foot of the ladder when placed 107m away from the wall, half of the ladder is extending above the wall. When the tip of the ladder is placed on the tip of the wall, how far is the foot of the ladder from the wall? 
  1.    100 √7 m
  2.    70√7 m
  3.    70 m
  4.    70√11 m
 Discuss Question
Answer: Option C. -> 70 m
:
C
 A Ladder Is Resting On A Wall Of Height       10√7m ...
Consider the abovefigure:
AD is the part of the ladder in the first case and AC is the ladder in the second case
AB = BD =10 7m [given]
2AD = AC [since AD is the half of the ladder AC]
By Pythagoras Theorem in ABD,
AD2 = AB2 + BD2
AD2 =(107)2+(107)2
= 2(107)2
AD=1072
Since AD is half of the ladder, the complete length of the ladder
AC = 2AD = 20 27
Now,
In ΔABC,
AC2 =AB2 +BC2
BC2=AC2AB2
=(2072)2 -(107)2
=(107)2[(22)21]
=(107)2×7
BC=107×7=70m

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