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Question
cos3x+cos5xsin2x+sin4xdx equals
Options:
A .  sinx−6tan−1(sinx)+c  
B .  sinx−2sin−1x+c  
C .  sinx−2(sinx)−1−6tan−1(sinx)+c  
D .  sinx−2(sinx)−1+5tan−1(sinx)+c
Answer: Option C
:
C
sinx=t;I=(1t2)(2t2)t2(1+t2)dt=(1+2t261+t2)dt
=sinx2(sinx)16tan1(sinx)+c

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